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6m^2-34m-180=0
a = 6; b = -34; c = -180;
Δ = b2-4ac
Δ = -342-4·6·(-180)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-74}{2*6}=\frac{-40}{12} =-3+1/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+74}{2*6}=\frac{108}{12} =9 $
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